So I went back and examined where I went wrong, however, I hit another snag.
So I did a= torque/Inertia, which got me to:a= rF/ [1/3 ML ^2]
a= maF/ 1/3ML^2
and then I get stuck because I have an acceleration value on both sides, and I feel like I'm going in the wrong direction
So I went back and examined where I went wrong, however, I hit another snag.
So I did a= torque/Inertia, which got me to:a= rF/ [1/3 ML ^2]
a= maF/ 1/3ML^2
and then I get stuck because I have an acceleration value on both sides, and I feel like I'm going in the wrong direction
Homework Statement
Consider a uniform rod of mass 12 kg and length 1.0 m. At its end the rod is attached to a fixed, friction-free pivot. Initially the rod is balanced vertically above the pivot and begins to fall from rest. Determine
a) the angular acceleration of the rod as it passes...