Recent content by tstl

So this is then the list of probabilities of the 7 species after one bond breaking:( un normalized). Is this OK docnet? P(A) = P(BCD) = 0.1 P(AB) = P(CD) = 0.7 P(ABC) = P(D) = 0.3 P(ABCD) = (1 - 0.1) * (1-0.7) * (1-0.3) = 0.9 * 0.3 * 0.7 = 0.189

This is not class homework but an actual research problem. The molecule in question is a toy example of a polymer. Under the mildest of condition we assume it undergoes a single breakage at a bond but as the condition becomes harsher it can break simultaneously at multiple bonds but that is out...

Thanks Docnet, So here are the probabilities before normalization of the 7 species after one bond breaking: P(A) = P(BCD) = 0.1 P(AB) = P(CD) = 0.7 P(ABC) = P(D) = 0.3 P(ABCD) = (1 - 0.1) * (1-0.7) * (1-0.3) = 0.9 * 0.3 * 0.7 = 0.189 Is this OK? I was previously doing P(ABCD) = (1 - 0.1) +...

Thanks docnet. Yes I want to consider the probabilities of finding the all 7 types. However I'm not sure what'll be the probability of each type say A and BCD when A:B breaks. Will it be (1/2) * 0.1 and (1/2) * 0.1 respectively (to be normalized later) because the Fragment pair has a probability...

I've a small molecule ABCD made of building blocks A,B,C,D. The molecule can get cleaved at any 'bond' between the building block one bond at a time. Researchers have compiled probabilities from dissociation studies of large number of molecules( made up of many other building blocks) and the...