Recent content by ttp88

sry -_- i just remember it.. they are moving in the same direction... If Source is moving Left... and away from observer... it shld be +10 and the observer is "chasing" after the source... so.. it shld be +10 too.. sorry ya..

sorry , u r Right . f ' = [(343+10) / (343-10)] * 100 --> Wrong f ' = [(343+10) / (343+10)] * 100 this is the correct one... finally ... i solved it .. =D thanx for helping me you !

No. Let`s see the Formula.. f ' = [(Velocity of Sound + Velocity of Observer ) / ( Velocity of Sound - Velocity of Source)] * Freq of source that is - f ' = [(343+10) / (343-10)] * 100 = (353/333)*100 =106 Hz therefor, f' > f there is doppler shift... BUT, Why ? what u say is...

i dun know... sorry because my english is poor =s let`s take an example... Given Values- Velocity of Sound = 343m/s Velocity of Source = 10m/s Velocity of Observer = 10m/s Frequency = 100Hz Question- When the Source is moving towards to the direction of Observer at 10m/s, at the same...

u mean Doppler Effect occurs in the situation ? Can u explain --Why--? since they have the same values of velocity V, how could the Doppler Effect occur ? the WaveFronts do not overlap, the observer is moving away from the source as well ,as they hv common of velocity.

the question is just liddat.. there is no any values... it is a conceptial question..the question given is just mentioned both of them moving in the same directoin and velocity... does Doppler Effect occurs ?

a Concept Question. Is there a Doppler Shift if the source and observer move in the same direction with the same velocity? Explain . Can someone drop their comments and ideas ..? please and thanks you.