Recent content by uberclay
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EV vs V, Cutoff Potential Question
Sorry - I copied it over wrong. The 1.989E-25 is (h * c), where h = 6.63E-34, so it should read Ek = [(h * c) / λ] - W = [1.989*10^-25 / 6.30*10^-7] - W Ek = 3.16*10^-19 - (1.5 * 1.60*10^-19) = 3.16*10^-19 - 2.4*10^-19 Ek = 0.76*10^-19 Joules Thank you for your assistance.- uberclay
- Post #5
- Forum: Introductory Physics Homework Help
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EV vs V, Cutoff Potential Question
So the e in the equation above is not for the conversion of joules to electron volts, but the elementary charge? And are my calculations correct?- uberclay
- Post #3
- Forum: Introductory Physics Homework Help
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EV vs V, Cutoff Potential Question
Homework Statement Light with a wavelength of 630 nm is directed at a metallic surface that has a work function of 1.5 eV. Find a) the maximum kinetic energy of the emitted electrons b) the cutoff potential required to stop the photoelectrons Homework Equations Ek = [(h * c) / λ] -...- uberclay
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- Ev Potential
- Replies: 4
- Forum: Introductory Physics Homework Help