Recent content by ultinator

ummm gravity, and the force that opposes the gravity, (equal and opposite reaction?) gravity and the retard force?

the pushing force across the handle the weight resisting back p.s. I won't blame you if you lose patience with me :(

force and displacement? or force and speed?

The other force acting would be the vertical component, and that together with the horizontal adds together to make x? but can't i take the horizontal component and use the cos function to establish x, like i attempted to do?

for horizontal component - Horizontal component (H) = x *c os30. 20N = 20kg x 1ms-2 = horizontal force needed. rearrange horizontal component formula to make x the subject - x = H / cos30 = 23N 23 N + 20N = 43N...? Am i going in the right direction roughly? Also i greatly appreciate you...

x (30o handle to horizontal ) = horizontal component (20) / cos 30 = 23.1 N ? apologies if i come across like an imbecile, but in my head I am thinking to move the mass with enough force to accelerate it by 1ms-2, then it needs to receive a horizontal force of 20N, then to apply those 20N from...

I'm a new member too - go easy (!) (I just read i was supposed to announce that first - sorry)

I guess the force needs to be equated to the horizontal orientation, but then i think of F=ma and with the mass and acceleration being 20*1 respectively. I end up think about a force of 20N pushing horizontally towards the right. It feels like I am missing something really obvious to do with...

Homework Statement Hello there, I have answered the first part by calculating the retarden force is equal to 80*cos30. This gave me an answer of 69.3N. I was wondering if someone could point me in the right direction to ascertain the force needed to accelerate the mass by 1ms-2 along the...