Recent content by ultrauser

  1. U

    Understanding Hammerthrow Forces, (no friction with ground)

    I can spin myself around in the air when I jump
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    Understanding Hammerthrow Forces, (no friction with ground)

    If I understand it correct during hammerthrow an athlete muscles cause Fcentripetal force on a ball and ball cause reaction Fcentrifual force on athlete. The athlete also cause Frotation on ball by rotating his body and ball cause Freaction on athlete. What would happen if athlete would try...
  3. U

    Lever and Acceleration: Greater Mass or Greater Accel?

    If I have 10m lever with a center of the mass 2m from the right side it must mean the shorter arm have greater mass to keep balance. Does it mean longer (lighter) arm have greater gravitational acceleration cause it must travel greater distance in the same time ?
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    Explosion force inside gun barrel

    But if the expanding gasses can go off when the barrel is open and can't go off if the the barrel is blocked shouldn't it mean the pressure is bigger or at least works for a longer time when the barrel is blocked (cause gasses have nowhere to go) ?
  5. U

    Explosion force inside gun barrel

    So does it mean the pressure inside barrel is higher if the barrel is blocked ( pressing with more force at the barrel causing it to explode)?
  6. U

    Explosion force inside gun barrel

    When I fire a gun there is an explosion inside a barrel that causes bullet to fly and gun to recoil but when a barrel is blocked a whole gun can explode, does it mean explosion inside barrel is stronger in second case?(The reason why I am wondering about it is because forces of explosion press...
  7. U

    How to understand Newton's 3rd Law

    There is one more thing I would like to know, what conditions needs to be met so the small planetoid m=10kg would hit big planetoid m=100kg and mantain it's direction (instead of being reflected)
  8. U

    How to understand Newton's 3rd Law

    F=10*(10 - -8.18)/0.001 = 181.8/0.001= 181800N ? (probably not xP)
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    How to understand Newton's 3rd Law

    I don't know how to do it (what formulas should I use) ? What I calculated earlier was average force needed to stop second planetoid (F= m*v/t ?) instead of force of actual impact?
  10. U

    How to understand Newton's 3rd Law

    The same example as above: u-velocities before interaction v-velocities after interaction So I know m1=100kg u1=0m/s m2=10kg u2=10m/s \begin{equation} v_1 = \frac{u_1(m_1-m_2) + 2m_2u_2}{m_1+m_2};\\ v_2 = \frac{u_2(m_2-m_1) + 2m_1u_1}{m_1+m_2}; \end{equation}...
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    How to understand Newton's 3rd Law

    Isn't it what I did in that example? What do you mean and how to do it? What do you mean by that? I thought if I have data and calculate force than calculation isn't assumption (and force is accurate)
  12. U

    How to understand Newton's 3rd Law

    I am calculating it like that (different masses example): planetoid 1 - standing ; planetoid 2 -constant velocity(<-- left direction) m1=100kg; m2 = 10kg v1=0m/s ; v2=10m/s time of impact t=0.001s F=m*v/t; F=10kg*10m/s / 0.001s = 100 000N a2=F/m2 = 100 000/10 = 10 000 m/s2 velocity...
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    How to understand Newton's 3rd Law

    But using this method velocity after impact of second planetoid would always be zero regardless of how massive or light (smaller mass) is the object it hits (when i throw rock at wall it is reflected not stopping)
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    How to understand Newton's 3rd Law

    I redid it without a given force and v1=0m/s v2=10m/s (<-flying left direction) time of impact t=0.001s F=m*a -> F=m*v/t -> F=10*10/0.001 = 100 000N a=F/m= 100 000/10 = 10 000 so acceleration is 10 000m/s2 in time 0.001s meaning change in velocity would be 10m/s ? It would mean left...
  15. U

    How to understand Newton's 3rd Law

    a=F/m a=200/10=20m/s2 but acceleration act in the time of t= 1/1000 s so the change in velocity will be 0.02 m/s ? and the final velocity v1=0 + 0.02 m/s=0.02 m/s and v2=10m/s - 0.02 m/s=9.98m/s ?? It seems like I messed up something here
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