Recent content by ultrazyn

i need help with this integral \int{e^x}{ln{x}}dx when i let u=ln(x) and v=e^x, i get \{e^x}{lnx}\ - \int{e^x/{x}}dx and then it keeps looping

limit as x approaches 0 of [(1/x^3) * integral from 0 to 3 of (sin(t^2))dt] is the way to solve this using mean value theorem for integrals? \lim_{x\rightarrow0}\frac{1}{x^3}\int{\sin{t^2}}dt the integral is from 0 to 3 not sure if i did the latex right