Recent content by United

I thought you calculated cg by calculating the value 1/3 to the left of your total "triangle" distance. On that basis is what I attained the answer 4m. What am I missing there?

To account for that I changed my 9 to a 6, used my moment equation, and still got a wrong answer. (10*6)/2 times 4, noting that the answer is negative because of direction What am I missing here?

I found the center to be 4 m (1/3 from the right side) into the triangle. I assumed the total load was 45N, based on (10*9)/2 (Weight * total length/2) based on this, I used my moment equation, and still got the wrong answer (noting that my force is in the negative direction) I feel my total...

Homework Statement http://imgur.com/gedpNxN Find the moment about point A due to the distributed load. Homework Equations M=force times perpendicular distance The Attempt at a Solution I tried multiplying 10*6, 10*3, 10*9 and plugging in their respective negatives as well, but I...

How do i find theta though?

Homework Statement http://i.imgur.com/Laub8lL.png Find the total moment created by force F1 about point A. Homework Equations moment = perpendicular distance x force The Attempt at a Solution I got my resultant distance to be squrt(20). With this in mind, I plugged into my...

Homework Statement http://imgur.com/7DDxqJp Find the moment generated about point O by the force, F1. Homework Equations Moment = Perpendicular Force * distanceThe Attempt at a Solution I tried plugging in that, because sqrt(3^2+4^2)=5, that my result would be either 6cos(30)*5 or 6sin(30)*5...