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How can we prove that a nxn real matrix A is a root of a given polynomial?
Thanks, but I don't understand clearly what you mean. And, is there any solution where theorem 1 isn't used for problem 2?- universedrill
- Post #3
- Forum: Calculus and Beyond Homework Help
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U
How can we prove that a nxn real matrix A is a root of a given polynomial?
Homework Statement 1) Prove that: nxn real matrix A is a root of f(X)= a[n].X^n+...+a[0].I, where a[n],...,a[0] are coefficients of the polynomial P(t)= det [A-t.I] 2) Let 5x5 real matrix A be satisfied: A^2008 = 0. Prove that: A^5=0. 2. The attempt at a solution I tried to solve problem...- universedrill
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- Matrix
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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U
Linear Algebra - Determinant Properties
Please help me with these: 1) Prove that: nxn real matrix A is a root of f(X)= a[n].X^n+...+a[0].I, where a[n],...,a[0] are coefficients of the polynomial P(t)= det [A-t.I] 2) Let 5x5 real matrix A be satisfied: A^2008 = 0. Prove that: A^5=0. Thanks.- universedrill
- Post #11
- Forum: Calculus and Beyond Homework Help