Recent content by usernamer

ooohhh... that clears up some stuff - (x is 0 for b because it will be the origin of its frame of reference, and same for a), I don't quite get your answers, but I can nearly get them... So. Because we're in b's frame of reference and want to find the distance between b and a, we use t=2 (the...

alright. cheers. ill ignore what that article said about proper time and length then, but anyway, I don't quite get why you did distance / gamma to get 0.866, ghwell. Like, what equation were you using? I think I followed what yuiop did to get 1.15 light years, and it seemed to make sense, but...

ok - I'll try to restate a couple of examples now, and explain what I currently think the solutions would be. I'll attempt to be clear... (atm I'm going with the definitions of proper time and length which are on http://www.mta.ca/faculty/Courses/Physics/4701/EText/Proper.html ) There's my...

Yeah, I in post #10, the situation I stated changed slightly, but does it really matter if you're measuring a distance between 2 points in space, or the length of an object (which is also, surely the distance between 2 points). Wouldn't the length contract the same amount? If so, then it...

Thank you everyone who replied, that was very helpful. I think I get it now. So... the proper length (which will have the largest value) would be measured by any observer which measures both ends of this object at the same time irrespective of their velocity. With proper time then, is the...

firstly, cheers for the replies so far, guys. Yeah. I'll try to make what I was trying to do a little clearer now, x'=\gamma x-\gamma v t = \gamma (x - vt) then subbing in some possible values for x, v and t: x'=\gamma (1 - 0.5*2) = 0 * \gamma (with units c=1, of course), so you've got...

ok - i do understand roughly what their purpose is, i think that if you have an object, a traveling at half the speed of light with constant velocity relative to another object, b which is at rest for 2 seconds, then, due to the effects of time dilation, the clock of a will slow so they actually...