Thank you. So then, solving for Q in terms of α1/α I get:
Q=me*e^[3π/α*(α1/α-1)]≈me*e^[645.6*(α1/α-1)]
For α1/α=2 I get 2E+280me. This appears to answer my question. :)
Before leaving I have two quick follow ups.
1) This is significantly larger than the plank energy. Would I be wrong to think...
Thank you for the link, but I am having difficulties using the formula provided. When I plug the values you give I don't get the values you give. The formula given is:
α1=α/[1-α/(3π)*log(Q^2/me^2)]
In particular, the log of 0 diverges to -infinity, so at 0 the formula goes to positive 0. That...
To contextualize your answer I am picturing something like
bare charge = coupling strength * e
in the limit where the length scale goes to infinity.
At what scale, then, is the coupling strength 2?
The charge of an electron is -e in energy scales well into the atomic scale. At infinitesimal scales it becomes infinite. This relation must be continuous for re-normalization to work, thus the intermediate value theorem asserts that it attains all values between at some energy level. I want to...
The limit of the function on both sides is 0, so the discontinuity is removable.
A more interesting function is
x(t) = 0, |t|>=1
x(t) = e^(1-(1-t^2)^-2), |t|<1
This displacement starts at rest, at -1 begins to increase, reaches a maximum of 1 at 0, then decreases and flattens out at 1...
I have a BS in Mechanical engineering. I took my theory to the physics instructor at the community college where I work for vetting, and it is he who said that the theory was beyond his capabilities to evaluate. He has a PhD in physics.
I think the boundaries established at link removed[/color]...
Thank you, though I think of it as a hobby.
Indeed, finding ways to phrase a question about an alternative theory as a question in a mainstream theory, and thus not violating forum rules, is tremendously instructive. As is arVix, when you get beyond that.
It has occurred to me that a pm to...
First of all, it appears that this idea has been tried and failed before. That is a sufficient argument against this idea.
You assert that there are plenty of places that allow and encourage these kinds of speculative discussions. I have yet to find one that will provide constructive...
I would like to suggest a new forum that relaxes the global rules pertaining to Overly Speculative Posts. I would offer the following alteration to the global rules for this one forum only:
XXX
Overly Speculative Posts:
One of the main goals of PF is to help students learn the current...
Thank you for confirming my thoughts. This appears to make his sites a haven for SR doubters. It seems the flaw in logic is outlined by TataKai in the following forum post.
http://mendelsachs.com/cgi-bin/forum/Blah.pl?b-MSFORUM4/m-1155004653/
Here it is argued that Einsteins postulates are...
What about the claim by Dr. Mendel Sachs that the twin paradox is itself not a valid interpretation?
http://mendelsachs.com/on-the-twin-clock-paradox/
I should note that a post asking for clarification on how, given two paths relative to a given inertial frame, the integral of time along the...
It is sci-fy, so, sure :)
It is likely the objects will be rotating, so the heating could be more uniform. Looking at the speed, assumed above to be 2x10^8m/s, (neglecting the fact that this is 2/3 the speed of light) with an atmosphere of thickness 5km, this gives us 25 microseconds for...
The object causing the Tunguska event was likely Cometary in nature, and 10 meters across. It delivered roughly 20Ktonnes of explosive power. Your object is 600 times more massive than an iceball 10 meters in diameter, suggesting that this should be similar to an H-bomb is 500 times more...
1) I am confused by the discussion above regarding the distance to the black hole. While the metric indicates the stretching ratio goes to infinity at the horizon, the actual distance integrated over the metric remains finite. Thus a waveform leaving the horizon at velocity c should reach an...