Recent content by utorontoconnor

Sorry, that was a waste of your time! Thanks again for all of your help! I look forward to your help again, hopefully! Cheers

Sorry- I think the textbook just has some typos...

Thank you! Really appreciate the guidance... Although, I appear to be off by a factor 1/10: Vmax=wA Amax=w^2A where w= Vmax/A, thus Amax=[(Vmax/A)^2]xA Hence, A= Vmax^2/Amax= 3.0625/18.6= .165m. Hence, w=1.75/.165= 10.60... though my text says it should be 1.06 or 10.6^-1... Where would my error...

Or am i able to isolate for A and then replug that into either equation to solve for ω?

Vmax= -ωA Amax=-ω^2A can I then equate ω=Vman/A? and the sub that into my Amax ω?

x'(t)=-wAsin(wt) So, if I want to maximize my velocity, I'd need to make sin(wt)=1, since sine oscillates between -1, and 1, the appropriate time would be at π/2? Hence, I would be left with x'(t)max=-wA(1) then, x''(t)=-w^2Acos(wt) would need to have cos(wt)=1 as well in order to get max...

Terribly sorry... I'm not sure what my first steps would be to find the angular frequency, ω, given a mass of 342-g attached to a spring undergoing simple harmonic motion, a max acceleration of 18.6m/s^2, and a maximum speed* of 1.75 m/s. Essentially, I don't know how to use F=-kx, x(t)=Acos(ωt...

Oops sorry... sequentially determine A) the angular frequency B) the amplitude, and C) the spring constant

Homework Statement A 342-g mass is attach to a spring and undergoes SHM. Its max accelerations is 18.6m/s^2 Its max velocity is 1.75m/s Homework Equations x(t)=Acos(wt) x'(t)=-wAsin(wt) x''(t)=-w^2Acos(wt) w=sqrt(k/m) The Attempt at a Solution I essentially derived these equations and have...