Recent content by v12alp

I have done it and computer says that all answers are wrong...now I'm trying to write two separate equations for displacement and make then equal and solve for time we'll see...

There is not enough info to calculate that...moreover there is no gravity present from what I understand. Considering if two objects are moving, especially one is pulling the other: there are to scenarios, either one is stationary and using some mechanism to pull the other towards itself (winch)...

HallsofIvy I re-read you message again and I have a question about your point: when you said that they have the same accelerations which is reasonable assuming taut's stretching is trivial, how in the world they suppose to meet? I mean we can neglect gravitational forces between then since the...

ok if they have the same motions they must have the same accelerations which means they will never meet? I thought about winch, but there is nothing in the problem shows it. Can you please tell me if Xf=Xo+Vot+1/2at^2 is the correct equation to use for it because honestly I have no clue what to...

it did not work, I'm not sure about one thing while tug is pulling asteroid, is tug moving? Ok I'm completely lost, I need someone's help badly, please!

Hi, yes, as a matter of fact I did. I assumed down direction to be negative so F=ma, a=F/m for the first the tug a (tug)=510N/m For the asteroid a=-510N/m (asteroid). From the formula Xf=Xo+Vot+1/2at^2 it became clear that Vo=0 m/s they started from rest and hence Xf-Xo=1/2at^2 or simply...

Hi everyone, this problem is truly pain in the a**. I understand that Newton's third law applies here, but whatever I have tried nothing worked out. I know that the force applied is the same in magnitude, but opposite in the direction and accelerations of these two masses are different...but no...