Recent content by V711

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    Solving a Container Pressure Problem

    1/ Note the cylinder drives the disk like a toothed belt for example. Like there is an axis of rotation all concentric forces can't rotate the cylinder. The only force F1 can rotate the cylinder. If there is F1, this force want to push the cylinder at right, but the axis prevent this, so the...
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    Solving a Container Pressure Problem

    The spaghetti will move inside the mouth. Here the cylinder move outside the container (P inside > P outside), correct ? There is a torque on the disque/cylinder with forces F1/F3, that torque moves the cylinder outside, correct ? My problem, is the sum of forces on the container, for me there...
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    Solving a Container Pressure Problem

    Yes, and what I can understand ? One end of the cylinder is inside and the other end is outside. What force is false ?
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    Solving a Container Pressure Problem

    No, sorry, it's a pipe full of material, I would like to say cylinder
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    Solving a Container Pressure Problem

    From P2 or P1 ? if it's outside it's P1, no ? The exercice guess P1=0.
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    Solving a Container Pressure Problem

    Homework Statement A closed container has a pressure P2 inside it. Outside there is the pressure P1 with P2 > P1. A pipe is enrolled on the grey disk. The pipe has a mass. The grey disk can rotate around itself. http://imageshack.com/a/img905/3235/Egzdk8.png 1/ Draw all forces with P1=0 2/...
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    Crossed Belt and Rotational Dynamics: Solving for Angular Velocity and Torque

    When the rotor of the motor is at +w, the belt don't move, correct ? So the rotor of the motor is at +w, why in this case the rotor of the generator is not at 0 ?
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    Crossed Belt and Rotational Dynamics: Solving for Angular Velocity and Torque

    so -9w for the rotor of the generator in the lab ref ?
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    Crossed Belt and Rotational Dynamics: Solving for Angular Velocity and Torque

    If I stop the motor, the belt don't move so the angular velocity of the rotor of the generator don't depend of the support, correct ? The rotor of the generator is at -10w. So the relative angular velocity of the rotor of the generator (ref its stator) is -10w-w=-11w ?
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    Crossed Belt and Rotational Dynamics: Solving for Angular Velocity and Torque

    If there is no support I'm agree because the rotor of the motor is at +10w so the rotor of the generator is at -10w. With the support, the rotor of the motor is at +11w not +10w and I don't understand why the rotor of the generator is not at -11w. Could you explain ?
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    Crossed Belt and Rotational Dynamics: Solving for Angular Velocity and Torque

    I don't understand could you explain ? The rotor of the generator is at -11w in the lab ref, is it correct ? it don't depend of the rotation of the support. But the stator of the generator is fixed on the support so it turns at +w, correct ? So why, the angular velocity of the rotor relatively...
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    Crossed Belt and Rotational Dynamics: Solving for Angular Velocity and Torque

    Homework Statement http://imageshack.com/a/img908/282/eCETrh.png The green support turns clockwise at +w around the white fixed axis. The stator of the motor is fixed on the support. The stator of the generator is fixed on the support too. The motor drives the generator with a crossed belt...
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    Angular velocity, torque and work

    If I resume: The support turns at +w (clockwise) The stator of the motor is fixed on the support so it turns at +w The rotor turns at +w relatively to the stator, so it turns at +2w in the lab ref The small pulley turns at +6w (lab ref) so it turns at 5w in the support ref, the small pulley is...
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    Angular velocity, torque and work

    yes, and like the angular velocity of the small pulley is 6w, on the support that angular velocity is 6w-w=5w, correct ? So I thought the work from friction is 5FRwt.
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