Recent content by Valdes
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Engineering equations involving correlated variables
Kinetic energy and speed are examples of correlated quantities. Two variables are correlated, in my sense of the word, if there exists a linear or nonlinear relationship between the two. The degree of correlation is measured by a correlation coefficient. My goal is to study the statistical...- Valdes
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Engineering equations involving correlated variables
Hello, I'm carrying out an assignment on the simulation of correlated (random) variables. Can you suggest to me equations pertaining to the field of engineering (or science) that involve correlated variables? My question may sound redundant, because all equations create dependencies between...- Valdes
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- Engineering Variables
- Replies: 2
- Forum: Engineering and Comp Sci Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
All right, this is what I get when I leave them as vectors: m*vector OX + M*vector OG = vector 0 m*vector OX = -M*vector OG m*vector OX = M*vector GO m*OX = M*GO m*20 = 1 m = 0.05kg Is this what you mean?- Valdes
- Post #13
- Forum: Introductory Physics Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
OX and OG are distances. If: vector 0 = (m*vector OX + M*vector OG) / (m+M) Then: 0 = (m*OX + M*OG) / (m+M) This is mathematically correct.- Valdes
- Post #11
- Forum: Introductory Physics Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
They're not vectors in that step, because if a vector A equals a vector B, then their distances are equal. That's what I did there, if the null vector equals an operation including vectors, their distances are equal. Am I right?- Valdes
- Post #9
- Forum: Introductory Physics Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
This is much more clear... the thing is, the question didn't mention which centre of inertia, the tyre's or the system's. Anyway, this is what I got when I replaced G' by O: OO = (m*OG1 + M*OG) / (m+M) 0 = (m*OX + 10*OG) / (m+10) 0 = (m*20 + 10*0.1) / (m+10) m*20 + 1 = 0 20m = -1 m = -0.05kg...- Valdes
- Post #7
- Forum: Introductory Physics Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
I'm not sure... I think it's a reference to the tyre's G. Could you help me in this case? (G=O)- Valdes
- Post #5
- Forum: Introductory Physics Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
Yes, I meant (m+M) and M, sorry. The G' I considered is the centre of inertia of the entire group, ergo the tyre and the object itself. X is to be attached to the cover of the tyre, the latter is considered as a circle, therefore X is to be attached at the radius R, yes. I think the centre of...- Valdes
- Post #3
- Forum: Introductory Physics Homework Help
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Find Mass of Object X for Centre of Inertia to Match Vehicle Tyre's Axis
Homework Statement The centre of inertia (G) of a heterogeneous vehicle tyre has a distance D=0.1cm from its axis of rotation (the tyre's). The axis is referred to as Delta. The mass of the tyre is M=10kg and its radius is R=20cm. O is the center of the tyre (belongs to the axis) Homework...- Valdes
- Thread
- Inertia
- Replies: 13
- Forum: Introductory Physics Homework Help