I know this is just a piece of whining, but I feel awful about it and want other's opinions. It wouldn't really bother if I didn't think I'm OK in physics.
In a question I had to calculate potential energy and naturally wrote the answer down as joules. However, when I came back to check the...
Thank you once again Bearded Man,
I finished the question. The only thing missing is some justification for the formula used (sum of series=...), but I understand if you don't have time to explain why it works.
I'm afraid we haven't done anything with sequences or series yet. That's why I think I'm doing something fundamentally wrong :). Could there be another way of doing this question?
It would be great if someone could point me to someplace where I can learn about sequences and series and...
Thanks for the answer,
I thought of them like that almost immediately after writing them down, but still can't get them into any other form. I understand that the exponent is always one more until it reaches n-1. I don't know how I can simplify a^n+a^m, which I think is needed here.
I asked about the first part of this problem in https://www.physicsforums.com/showthread.php?t=592408. I thought the best idea was to start another thread for the second part.
Homework Statement
Part a) Given f(x)=ax+b, and f(3)(x)=64x+21, find the values of the constants a and b.
(note...
Thanks a lot; I don't understand how I didn't notice that.
This is how I got the answer in case anyone's interested:
a^3x+(a^2b+ab+b)=64x+21
Therefore a^3=64 => a=4
a^2b+ab+b=21
=> b(4^2+4+1)=21 => b=21/21=1
Thank you
Given f(x)=ax+b, and f(3)(x)=64x+21, find the values of the constants a and b.
(note: f(3)(x) means fff(x))
To me this seems like I have to use two equations to find the value of three variables, since when I have found a and b, I should be able to get the value of x. Even though it...