Recent content by vanquish

I'll keep that in mind, but it accepted the answer. Thanks for sticking with me, I can be slow sometimes, I really appreciate it and I do think I learned from this, which is always a good thing.

oh wow Ax=At*cos(8.5)+An*sin(8.5)=-2.41 m/s2 Ay=-16.14 m/s2 EDIT: -2.41

if at=0 then when i take the pojection of At along Ax i get Ax=At*cos(8.5)

well if at=0At=0 An=v^2/ρ=75^2/344.6=16.32 Ax=0 Ay=16.14

vt and at

velocity and acceleration?

ds/dt=75 d2s/dt2=0

according to my book: atds=vdv so at=vdv/ds v=75m/s and dv/ds=-3x/1000 and since we want At at 50ft dv/ds=-.15 so at=(75)(-.15)

I think I got it, At=11.25 An=v^2/ρ=75^2/344.6=16.32 So when i calculated everything and used the angle i found before to project this information from the At and An directions into the Ax and Ay directions I get these numbers: Ax=11.12 Ay=16.14

the only things my textbook says about this are: at=\dot{v} or atds=vdv

a=(75ft/s^2)ut+(v2/ρ)un At=75ft/s^2 ? An=v^2/ρ=75^2/344.6=16.32

75ft/s?

i don't think i can find either of them because i have no time, Vt is d\theta/dt*radius

I sure would. At=dvt/dt=r \alpha

alright, but I am still not quite sure what the correct equation is supposed to be a=(d2y/dx2)ut+(v2/ρ)un