Recent content by vanquish

  1. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    I'll keep that in mind, but it accepted the answer. Thanks for sticking with me, I can be slow sometimes, I really appreciate it and I do think I learned from this, which is always a good thing.
  2. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    oh wow Ax=At*cos(8.5)+An*sin(8.5)=-2.41 m/s2 Ay=-16.14 m/s2 EDIT: -2.41
  3. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    if at=0 then when i take the pojection of At along Ax i get Ax=At*cos(8.5)
  4. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    well if at=0At=0 An=v^2/ρ=75^2/344.6=16.32 Ax=0 Ay=16.14
  5. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    vt and at
  6. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    velocity and acceleration?
  7. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    ds/dt=75 d2s/dt2=0
  8. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    according to my book: atds=vdv so at=vdv/ds v=75m/s and dv/ds=-3x/1000 and since we want At at 50ft dv/ds=-.15 so at=(75)(-.15)
  9. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    I think I got it, At=11.25 An=v^2/ρ=75^2/344.6=16.32 So when i calculated everything and used the angle i found before to project this information from the At and An directions into the Ax and Ay directions I get these numbers: Ax=11.12 Ay=16.14
  10. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    the only things my textbook says about this are: at=\dot{v} or atds=vdv
  11. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    a=(75ft/s^2)ut+(v2/ρ)un At=75ft/s^2 ? An=v^2/ρ=75^2/344.6=16.32
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    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    75ft/s?
  13. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    i don't think i can find either of them because i have no time, Vt is d\theta/dt*radius
  14. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    I sure would. At=dvt/dt=r \alpha
  15. V

    Van travels over the hill described by y=(-1.5(1/1000)x^2 + 15)ft

    alright, but I am still not quite sure what the correct equation is supposed to be a=(d2y/dx2)ut+(v2/ρ)un