Recent content by Vapen

I believe your s term is wrong, it seems that it should be the reciprocal of that. \frac{1}{RC} + \frac{R}{L} Just in case anybody else sees this post.

Okay, that's initially what I thought I had to do when I read this question. The constant in the denominator (the 2) was the part that I was confused about. I realize now that the numerator, when constant, will have no effect on the denominator when finding a value for \omega_0. Thanks for your...

Sorry, I typed that wrong. X(s)s^2 + 2\zeta\omega_0X(s)s + \omega_0^2X(s)=F(s) H(S) = \frac{X(S)}{F(S)} = \frac{1}{s^2 + 2\zeta\omega_0s + \omega_0^2}

Hmm ok, you edited the previous post. H(s) = G(s) Then: \frac{X(s)}{F(s)} = \frac{1}{CLs^2 + \frac{L+R^2C}{R}s + 2} \frac{s^2 + 2\zeta\omega_0s + \omega_0^2}{F(s)} = \frac{1}{CLs^2 + \frac{L+R^2C}{R}s + 2} But I'm left with the F(s) which I cannot do anything with? I found the poles to both...

I understand that part, but I still don't know what you mean by applying that second order differential equation to this. Are you implying that I need to know the actual values for the forcing function to characterize this circuit?

I don't understand how I would apply that. \ddot{x} + 2 \zeta \omega_0 \dot{x} + \omega_0^2 x = 0 After Laplace transform (assuming initial conditions are zero): X(s)s^2 + 2\zeta\omega_0X(s)s + \omega_0^2X(s) Are you suggesting to equate this to the denominator? Your reply is ambiguous, I...

Homework Statement [PLAIN]http://img534.imageshack.us/img534/228/helps.png I have trouble completing (b), as I do not know how to solve for the damping factor in this circuit, and hence cannot characterize this system. I have the poles of the system, where s ~= -3048.059 and s~= -8201.941...