Recent content by vebjoern

Thanks for a good answer! :)

the Torque around A from the force B_y should then be equal to 0,because of that the vectorproduck = 0, and therefor the Torque around A from the forces could be that r1*FBx*sinθ = r2*FGysinΦ where r1 should be ½*L and r2 should be √((¼*l)2+(½*d)2) ?

is it wrong to write that the Torque from hing A to point C = -d/2*Mg ? where d/2 would be the lever-arm and (-) because of the clockwise rotation ? ?

but shouldn't the forces from hing A and B have opposite directions in the x-axis to get static equilibrium?

i am studying electronical-engeneering in Norway, and i am also interested in physics, and would like to learn more about it :)

i understand now! thanks

but what about the mass of the car ? wouldn't that have anything to say about the required T ?