Recent content by velocity9

Thank you so much for your patience! It all makes sense now

Ok, so I found that mutiplying the d/v that we were discussing by 2pi works. I realize the units are convenient as we had discussed since all we are left with is seconds. I'm not entirely sure why the 2pi worked. I was searching about period and I noticed most of the periods had 2pi written next...

I know the velocity since I found it in the first part. I used and found v = 6.19*10^5 m/s I think the time to cover that distance would be the period. If I could find the distance, I could probably use simple v = d/t and rearranging for t=d/v, I think the units cancel to leave you with seconds...

For the second part of the question, it asks: What is the period of revolution for the atom in the previous question? I'm having a little bit of trouble deciding what is related to what. I figure I can use ω = 2π/T the velocity found.. that is ω, right? Not sure how else they could be...

gaah yes you are right! So sorry for the silly mistake. I had it written down correctly but my brain wouldn't convey the information to my fingers when plugging into the calculator. Thank you so much for your time!

I got 437740 m/s for the speed

Homework Statement A doubly charged helium atom (mass = 6.68 x 10-27 kg) is accelerated through a potential difference of 4.00x 103 V. What will be the radius of curvature of the path of the atom if it is in a uniform 0.460 T magnetic field? Note: I hope this question is meant in advanced...