Recent content by Vermillion

Just for quick clarification, you mean like this? Horizontal Components \SigmaFx = 0 F - f.cosx - mg.sinx.cosx = 0 Sorry, I'm not used to talk physics in english.

Do you mean, i should throw in F.Sinx to my friction equation? Which i forgot to do.

Thanks Tim, I corrected the plus-minus mistake. It should be F = mg(\mu + tanx) Then the acceleration of the prisms is F = (m + m)a F = 2ma 2ma = mg(\mu + tanx) a = \frac{g} {2}(\mu + tanx) Finally, i don't know how to relate the acceleration to the friction. Can you explain it to me?

Homework Statement A prism has the mass m with the angle x = 45°(look at the picture) placed on the ground without friction. The other prism, which has the same mass m, is placed above the first prism(the first prism is bigger). A horizontal force F is given to the second prism so the...

Yeah i think that's what the question meant. Thanks for the help! :)

You're right, i forgot the velocity is not constant. Then i should use s = v0t + \frac{at^2}{2} Because the car was resting then v0 = 0 s = \frac{at^2}{2} s = \frac{gt^2(t3-t1)}{2(t4-t2)} Is that correct?

Oh wow thanks! I actually never knew that tension forces always pull away from the object they act on, duh... As for the 2 equations of m, i needed them to solve the a(acceleration) in t1, t2, t3 ,t4, and g. My third equation is actually m = m. Sorry, i didn't type it. I think i have done the...

Hi, I'm new here. I have a problem. Homework Statement A box has the mass m, held by two horizontal ropes and two vertical ropes. The box is inside a still car. If the car accelerated suddenly with the accekeration of a then the box will remain still inside the car. What is : a. The...