Recent content by Vidar Martinsen

Thank you all again for giving me a greater understanding of these things :) Regards Vidar

I was to fast here, and did not read your answer first. If I understand it correctly all matter will have the speed of light at the event horizon. So the answer is. Since she has the speed of light, time will stand still and there will be a total length contraction looking outwards. Ok thanks...

Another question is of course: How fast speed will you experience at the event horizon if you are falling in from a significant height?. If it is close to light speed, you will of course experience a significant time dilation and length contraction looking outwards.

Ok , Thanks. So what you say is if she somewhat manages to stay put for a short time at the event horizon due to a sort of infinite rocket power trust outward, she would experience time outside go at infinite speed. Of course it is a theoretical situation, but I just wonder about the behavior...

Thanks for all your explanations. I se that nobody has claimed my assumption to be false. My point is : If what I am claiming is true ( Allice experience time outside the black hole run at infinite speed). She will never enter the black hole at all, and never cross the event horizon because...

Lets look at the known story of Alice and Bob outside a Black hole. Alice are falling inn to the hole, and Bob are outside. What would Alice observe from the event horizon of a Black hole. Looking outward. We know Bob who is outside, se Allices clock standing still, but Allices clock are not...

If I understand this correctly: Is it safe to say that you bouth are right because you accually are talking abaut to differents eventes in time. 1. When the spaceship sees the event. ( it happened 50 y ago to the spaceship) 2. When the event happened on the star ( The spaceship was (or shoud...

Yes, I agree. Not to confuse other reders. The numbers in the formula should also be: t=2(-100-(0.87*100/1)) berceuse i set light speed to 1 and the formula is c2 so 12 shuld be 12 = 1. Yes i realize this now because light from distant objects reaches us at the same time if we are in...

Thanks a lot for your responses. I found a formula that gave the same result. Is this the right formula?: t = lambda (t’- (vx/c2 )) if we put in the numbers: Can we use ly and c=1 together in the same formula? I så the: lambda = 2 c = 1 v=0.87 (87% speed of light) x = 100 (100 ly away...

Thanks a lot :smile: I suspected it must be something like this, because I won't dare to thing about the consequences if my conclusion where true :woot: I will try to find the math to understand why this is so.

If you are in a space ship, traveling near light speed, will length contraction enable you to se astronomical events lightyears away, before it is possible to see them from earth? This because the distance is shorter for you in the spaceship and light speed is constant. Example: A star 100 ly...