I'm saying that because gear has more diameter than shaft and from your question can i understand that shaft just deliver power to any thing connected to it i.e same torque and same speed.
And coming to the formula i got it here...
Final question(i think i can understand fully with this)
Let the diameter of shaft S1=S2=19mm and S1 is a motor shaft rotating at 3000rpm.
from rpm=(kmphx1000)/(60xA) the speed of shaft is 10.744kmph
The gear G1 with diameter 150mm rotates at 380rpm and the gear G2 rotates at 190rpm(got from...
But actually rpm is inversely proportional to diameter of the rotating object then if gear ratio i.e. the ratio of diameters is 2:1 then i think the rpm is 1:2. Is it true?
Sorry i thought that gear ratio as the ratio of their speeds.
And what happens to the shaft rotation will they rotate...
Hi all,
I'm an EE student and i have least knowledge about working of gears.
I just want to know that if there are two shafts S1 and S2 of same diameter having two gears G1 and G2 mounted on them respectively. The gear ratio is 1:2. And the shaft S1 is connected to a motor which rotates at...
I think i found my answer here https://www.physicsforums.com/showthread.php?t=492606
post 7 first paragraph
a charger is also same as AC DC adapter which does the same thing. am i right?
Thanks uart so from your reply i understand that input current is more than rated even then4 the input power is more. And even we take power factor into consideration it is more than output DC power. Now what I'm asking is can't we take the same amount of power which is consumed by the mobile...
Hi friends, I have a samsung mobile charger with specifications as
Input: 150-300V AC and 0.15A
Output: 4.75V DC and 0.55A
So now by P=VI
the input power is 36W (taking 240V AC and unity PF)
and output power is 2.6W.
So my doubt is why there is such difference the power of i/p and o/p...