Recent content by vidit jain

Is there a way of creating a potential difference without a field?i should think that a strong field Is created when I connect an appliance to a socket which causes a potential difference

hey, so I learned about capacitors and one particular detail about capacitors that is stressed upon is that the field of a capacitor is contained between the plates of it( assuming the field from the edge of plate to be very small). So my question was that when we short a capacitor, why does the...

There is a definite speed with which the electrons can move ,even on a conductor. So yes, there would be a momentary 'local charge' before the electrons distribute over the conductor. If some electrons are lost from the conductor, the 'positive charge' thus created will spread over the...

So when you find the work done when u push the box from A to B and back, you really need to consider every moment. U start pushing the box. U push the box a nanometer. stop. find the work by taking the (dot) product of force and displacement. U again push the box 1 nanometer .stop. Again find...

U must decide what is positive and what's negative. Since u have taken acc due to gravity as negative, going up will be considered as positive displacement . The initial position is 3.6 m ABOVE the ground. And the final position of the ball is on the ground. So the initial d becomes +3.6. And...

The d in the formulae Is the net displacement . Since d initial is 3.6 and d final is 0, d net becomes -3.6

Assumption:A light push is given to the marble.it starts to fall with 0 velocity. The moment when the ball 'leaves the sphere' is when the normal force between them is 0. Apply conservation of energy and make an expression for centripetal force at the instant when the normal force exterted by...

Since the angular momentum depends on then cross product of the position vector and momentum vector(which is in the same direction as velocity),the formulae for the angular momentum maybe written as mvrperpendicular. (The cross product of the component of r vector along/parallel to...

This may be proved using gauss law. But this must be left for the OP to demonstrate as per the PF guidelines.

I agree with this, and this is essentially what I wanted to say. But in order to find the electric fields at various positions, we need to find ηtop and ηbottom individually. That may be achieved using gauss law. The charge of the plate will always be confined to the plate but it may move...

I missed a 2 in the denominator. was that the error? If not, what would be the correct expression?

(ηtop)/2ε

Since it's a plane , it has a thickness approaching 0. Assume the plane to be z=0. Now all the charge on the plate is confined to z=0+dx(just above 0) and z=0-dx(just below 0). Since the positive charge from the plate attracts the charge on the plane, the charge would be concentrated towards the...

If we consider the plane to be very thin,[lets say an atom thick], it can be treated as a conductor and that leads us to conclude that the charge is free to move either to the upper side of the plane or to the lower side. If due to some reason, the assumption of taking the plane as conducting...

Yes,it must be.all the charge on the bottom plane rushed upwards,leaving the lower surface neutral and the upper surface(of the plane) negatively charged.