Recent content by vilhelm

Ok, so first the precious question, and now: I try to find primitve functions. Wolfram Alpha primitive \frac{1}{x^{2}-x+1}-\frac{x}{x^{2}-x+1} - Wolfram|Alpha and I disagree My answer is this 4/3arctan(?4\?3*(x-1/2))+1/2(ln(x^2-x+1)+4/3arctan(?4/?3(x-1/2 - Wolfram|Alpha))) And here are my...

Re: Inequality with abs Would this be a better answer "for x<-1 we have x<1 and for x>-1 we have x<5" since it's a bit more broad?

Re: Inequality with abs Isn't $x<5$ the correct answer?

Re: Inequality with abs I tried this (you can pretty much ignore the table and go straight to case a and case b. http://cl.ly/image/1Z1O0j1E2a0y

Solve 2x - |x+1| < 4.

But for the arctan(u) and ln(1+u^2) should I take the limit as n goes to infty? How is that done? Thanks.

And in this case, a is indeed $-\infty$ and b is indeed $\infty$.

So the view that integral from a to b for f(x) is the area under that curve, is not an exact view in this case?

Wouldn't it be very obvious how it behaves when x approaches infty – since for very large x, the denominator would be very large, but the numerator is periodic. So the fraction approaches 0. Correct or wrong?

So, I'm correct?

What about this argument: we know how the graph of sin^2(x) looks, since we can write it in terms of cos(2x). and sin^2(x) is divided by x, so we can actually understand how the graph looks for any x except zero (put it in you grapher and see). for the given function, we have f(x)=-f(-x) for...

Sorry, wrong image. Here is the correct one. https://www.dropbox.com/s/bghijxpzobb1f5o/2013-10-27%2020.26.56.jpg

Here is my attempt. I'm still a bit stuck... https://www.dropbox.com/s/9gub6zq02b5235b/Screenshot%202013-10-26%2021.13.45.png

Here is my attempt https://www.dropbox.com/s/fsdkk8a189lk54o/2013-10-26%2015.38.38.jpg

First calculus course, so I have not learned that. - - - Updated - - - Thanks, I'll try it and update with my progress.