Fully understood... but he used the basic premise to develop a rather complex integration to calculate heat loss and heater sizing, devoting an entire chapeter to the subject and using the results as the basis for fundamentals in other chapeters.
There is a second edition to the book and I...
That leads me to question the entire validity of the information in the book. How could the author make such a blatant error and use that error to derive an entire formula for sizing heaters and other equipment? I am simply stunned.
So again, what I am missing here?
You would multiply cal/sec by 4.186 to get watts, not by 0.23889
1 Watt = 0.23889 cal/sec = 3.41 btu/h
1050 Watt = 251 cal/sec = 3583 btu/h
That matches every calculator and example I can find online. Yet, the author multiplies by 0.23990 instead of...
Lets take a step back here because I think the very basic question and reasoning is being lost. I don't wish to sound ungrateful, but I am struggling to understand this information and this exchange has only confused the issue.
My question is not being answered and you are isntead distracted...
please move this back to the physics forum! I am not a student, nor is this coursework or homework. I am an adult seeking help understanding a physics concept, not a student looking for homework help[/color]
I have made serious edits to the post above. I at first used the 4.44 DeltaT instead of the new 8.3 DeltaT
So with the listed glass tank and a 15 Degree F (8.3C) temperature differential between the tank and room, he predicts a 169 Watt thermal loss to the room and the standard conductivity...
Sorry, I rounded in my posts... I used more decimal places in the spreadsheet for k (0.00238933) . Small changes in k equate to fairly large swings in heat flow :)
The book does not give a result, only the equation and the additional instructions that:
[/i]
His outcome for a 3/8" thick 12"...
Forgive the stupidity, but I am still lost.
The author lists Q as calories. The time entered into the equation is 1 second. The result is Q = 251.85 calories in one second. That equates to 1053.698 Watts (unless I am not understanding something).
0.239 cal/sec = 1 Watt
251.85 cal/sec =...
Hello... first post here so take it easy on me.
From the Book: "Aquatic Systems Engineering: Devices and How They Function, Selection Installation Operation" by P.R. Escobal
In the section about heat loss (section 12.9) the author gives the basic conductivity equation in the form:
Q =...