Hey willem2,
Thanks for the reply.
Yes, I did have that idea earlier, but I was trying to answer the following: If I've a blackbox that has the circuit you mentioned i.e. switch and a resistor with no access to internal nodes and I need to have a DC equivalent of the original source that...
I've a theoretical circuit that resembles an on-off switch with a duty cycle of 50%. The voltage input to the circuit is a constant 5v. The current drawn from the source is 1A when switch is ON and 0A when OFF. What is the Vrms and Irms?
From what I know:
Vrms for constant 5v is 5v.
Irms...
As I understand, the statement made by me earlier is indeed true. Immaterial of values of capacitor and resistors, the capacitor would store half the energy supplied by the battery. The power delivered by the battery in charging a capacitor of value 'C' to voltage 'V' is C*V^2. The energy stored...
In case the charge doubles, the voltage would also get doubled. Hence stored energy would get quadrupled. All the formulas would yield the same result.
The capacitor stores half the energy supplied by the battery. Remaining half is lost in the resistance (resistance of wires used) as I*I*R. The energy lost in the resistance is independent of value or resistance and depends primarily on the capacitance.
With equivalent capacitance, first calculate charge with Q=CV.
Then calculate voltage across 3uF using V=Q(as obtained above)/3uF
Voltage across the parallel combination of 1uF with series combination of 2uF and 5uF will Vab (300v)-V(across 3uF, as obtained above, in step 2). This will be...