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    Solving Log Equations (Different Bases)

    Here's an alternate solution: 2(3^x)=7(5^x) 2/7=(5^x)/(3^x) Divide both sides by 7 and by 3^x 2/7=(5/3)^x log(2/7)=log((5/3)^x) log(2/7)=x log(5/3) log(2/7)/log(5/3)=x
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