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Dimension of orthogonal subspaces sum
Yeah, they are indeed just numbers. About the triangle inequality maybe it is something to do with the fact that if we take a vector which has component representation in an orthonormal basis of all ones: $$\begin{bmatrix} 1 \\ 1 \\ ... \\ 1 \end{bmatrix}$$ Then the inner product of this vector...- Virgileo
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- Forum: Calculus and Beyond Homework Help
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Dimension of orthogonal subspaces sum
##| V_1 \rangle \in \mathbb{V}^{n_1}_1## and there is an orthonormal basis in ##\mathbb{V}^{n_1}_1##: ##|u_1\rangle, |u_2\rangle ... |u_{n_1}\rangle## ##| V_2 \rangle \in \mathbb{V}^{n_2}_2## and there is an orthonormal basis in ##\mathbb{V}^{n_2}_2##: ##|w_1\rangle, |w_2\rangle ...- Virgileo
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- Dimension Orthogonal Subspaces Sum
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- Forum: Calculus and Beyond Homework Help