Recent content by vitus

I see so it becomes MbVbix + MwVwix = -MbVbfx + MwVwfx which, since everything is at rest initially, becomes: 0 = -MbVbfx + MwVwfx MbVbfx = MwVwfx (5 kg)(6 m/s) = (10 kg)(Vwfx) 0.5(6 m/s) = 3 m/s Seems rather obvious now that you point it out. Thanks.

Homework Statement A large Wedge with mass 10 kg rests on a horizontal frictionless surface (think right triangle on a unit circle, theta <90 deg.). A block with a mass of 5 kg starts at rest (near the top) and slides down the inclined surface of the wedge, which is rough (does this imply...