looooooooooool, I think I have too much misunderstanding! o.O
I really fully appreciate your help
thanks (micromass), thanks (Char. Limit)
and I'm sorry for my bad English ^_^
good night to all :)
I couldn't reach the same form of the Final answer :(that's what I did:
f(c)= -e^-1
f'(c)= e^-1 - e^-1 = 0
f''(c)= 2e^-1 - e^-1 = e^-1
f'''(c)= 3e^-1 - e^-1 = 2e^-1then I substitute in the formula:
f(x)= f(c) + f'(c).(x-c)/1! + f"(c).(x-c)^2/2! + f'''(c).(x-c)^3/3! +...+ fn(c).(x-c)^n/n!+...
Thank you very very much :)
but, what should I do to find f(c),f'(c),f''(c), and f'''(c)?
the formula we have studied in the class looks like this:
f(x)= f(c) + f'(c).(x-c)/1! + f"(c).(x-c)^2/2! + f'''(c).(x-c)^3/3! +...+ fn(c).(x-c)^n/n!+...
reaaaaaally! :eek: :cry:
excuse me because I'm beginner :redface:
so,
f'(x)= e^x + xe^x
f''(x)= e^x + e^x + xe^x, and
f'''(x)= e^x + e^x + e^x + xe^x
is that correct? if so;
can i sum (e^x) with each other??
so it becomes
f''(x)=2e^x + xe^x
f'''(x)=3e^x + xe^x
hmmmmmmmmmmm
i'm not sure, but let us say:
(e^x) remains as it is= (e^x)
and (xe^x) will be =(e^x + xe^x)
so the Ans. should be= e^x + e^x + xe^x :frown:
Hi everybody, I hope anyone could help
Homework Statement
Find the first three terms of the Taylor series for f(x) at c.
http://dc12.arabsh.com/i/02388/kgybq4dwkug3.png
Homework Equations
f(x)= f(c) + f'(c).(x-c)/1! + f"(c).(x-c)^2/2! + f'''(c).(x-c)^3/3! +...+...