Recent content by vortex2008

looooooooooool, I think I have too much misunderstanding! o.O I really fully appreciate your help thanks (micromass), thanks (Char. Limit) and I'm sorry for my bad English ^_^ good night to all :)

ooooh I see! thanks guys, but what about vectorial 3? (3!) it shouldn't be 6 ?

This is my answer: and this is the answer in the back of the book:

I couldn't reach the same form of the Final answer :(that's what I did: f(c)= -e^-1 f'(c)= e^-1 - e^-1 = 0 f''(c)= 2e^-1 - e^-1 = e^-1 f'''(c)= 3e^-1 - e^-1 = 2e^-1then I substitute in the formula: f(x)= f(c) + f'(c).(x-c)/1! + f"(c).(x-c)^2/2! + f'''(c).(x-c)^3/3! +...+ fn(c).(x-c)^n/n!+...

Thank you very very much :) but, what should I do to find f(c),f'(c),f''(c), and f'''(c)? the formula we have studied in the class looks like this: f(x)= f(c) + f'(c).(x-c)/1! + f"(c).(x-c)^2/2! + f'''(c).(x-c)^3/3! +...+ fn(c).(x-c)^n/n!+...

reaaaaaally! :eek: :cry: excuse me because I'm beginner :redface: so, f'(x)= e^x + xe^x f''(x)= e^x + e^x + xe^x, and f'''(x)= e^x + e^x + e^x + xe^x is that correct? if so; can i sum (e^x) with each other?? so it becomes f''(x)=2e^x + xe^x f'''(x)=3e^x + xe^x

hmmmmmmmmmmm i'm not sure, but let us say: (e^x) remains as it is= (e^x) and (xe^x) will be =(e^x + xe^x) so the Ans. should be= e^x + e^x + xe^x :frown:

Hi everybody, I hope anyone could help Homework Statement Find the first three terms of the Taylor series for f(x) at c. http://dc12.arabsh.com/i/02388/kgybq4dwkug3.png Homework Equations f(x)= f(c) + f'(c).(x-c)/1! + f"(c).(x-c)^2/2! + f'''(c).(x-c)^3/3! +...+...