G-force is actually a measure of acceleration, so you cannot gain or lose a significant amount after an object is far away from a planet. The "slingshot effect" fully relies on the velocity of the planet in the view of an observer. This maneuver is only useful if the planet is moving in the...
Ah, okay. :) But to quickly answer your first question in your first post, take a look at the graph I posted a few messages back. As your initial model suggests, the object is accelerating 9.8m/s^2 downward. This means that for every second, the velocity is being deducted by 9.8m/s. You can...
I'm not sure I understand the question you are asking. If you restate it, I would gladly help you.
Also, do you have knowledge of summation \inline{\sum} or calculus?
Not proved, but close enough for your purposes. Mathematics is the only branch of science that is not considered proven using experimental means.
For a bonus, imagine you have an object accelerating at a changing rate. The velocity could be expressed as, say \inline{V(t) = A\sin(\omega t)}. By...
If the video has a timestamp with milliseconds or hundredths of seconds or a constant framerate, you can calculate the speed with enough accuracy. Estimate the distance of a specific point on the car between two frames and divide it by the time between the frames you are comparing. Of course you...
Your questions 1 and 2 are fully answered with calculus. The function v(t) = -9.8m/s^2 \cdot t represents the velocity of the freefalling object at a given time t.
Integrating the equation, we get
d(t) = \frac{-9.8m/s^2}{2} t^2 \,,
which describes the function of displacement. In other words...
Berry, I suggest a few books before you get your hopes up about your current project. It's great that you strive for alternate power sources, but perhaps more knowledge on the subject would benefit you even more.
https://www.amazon.com/dp/0071439250/?tag=pfamazon01-20...
The voltage of the battery is constant, so you should not see a speed decrease until the battery is nearing its death. Give it a few hours or even days, and it should stop running.
I assume the battery will die soon. As you said, the motors are giving off heat. Since the heat energy must come from somewhere, the battery should now be gradually losing its electric potential energy.
In a machine like the one you're describing, part of the electrical potential energy of the battery is being converted to sound, heat, and other vibrational kinetic energy. No matter the quality of the generator or motor, you will always lose energy from your system.
Even if you managed to...
I find these definitions of the golden ratio very elegant:
\phi = \sqrt{1 + \sqrt{1 + \sqrt{1 + \cdots}}}
\phi = 1 + \frac{1}{1 + \frac{1}{1 + \frac{1}{\ddots}}}
The proofs of these are interesting as well.