Recent content by weehian

thanks claudius, I'm very glad to hear that. my total apparent power my aquarium equipment is about 2.5kwh, while the sum of the stated power consumption of each equipment adds up only to 1.5Kwh. very glad that I'm actually paying for the latter. :smile: thanks for all the very prompt...

thanks russ for the link to the excellent article and explanations. I'm clear about this topic now. :smile:

thanks claudius2 for your very detailed explanation. if that's the apparent power that i measured, it will not be reflected accurately in my electricity bill right? i'm actually calculating how much power my aqurium pump is drawing and how much I'm paying for it. my aquarium pump states a...

thanks Clausius2 and Russ, i understand that in most households, power companies charge users based on the resistive power, which is measured using a watt-hour meter. (pls correct me if I'm wrong) I do not have a separate watt-hour meter at home to measure power consumption of each...

to measure the amount of power drawn by an appliance, can we simply multiply the voltage (V) of the mains by the current (I)drawn (measured using a digital clamp meter) by the appliance to obtain power (P=I x V). does the power company charge us (rate x Power) based of this value P, regardless...

thanks russ, how nice if we can make a huge a evaporator to sit in the north and a mega condenser and compressor to sit and the south and connect all of these together with a refrigerant. during summer in the north, ppl will be comfortably cooled and ppl in the south who are having winter will...

ThaNKS Clausus2, the equation solves the puzzle. and thanks for helping me understand this topic. From many airconditioners, seems like the Qcondenser forms a bigger part of the equation than the Wcompressor. Eg. 500W(compressor) of power into the compressor can cool down 1500W(evaporator)...

i think i know for how the aircon extracts more heat energy than the amount of electrical energy input and at the same time obeying the laws of thermodynamics. the answer lies in the efficient condensor that cools the hot compressed gas before it is allowed to be expanded in the evaporator...

thanks brewnog, u gave a good analogy. are you said that 500W is the amount of energy needed transfer the 1500W of heat out of the room. my understanding of aircon cooling is that the compressor mechanically compressess and almost ideal gas to increase its internal energy. this will mean...

i see thanks nenad. is there a theoretical maximum amount of heat that the compressor can remove based on the joules constant? sorry, i did not get to study about it in school. i found out that joule constant is 4.186J/cal and that 4.186Joules=1calorie. if that's the case, the joule constant...

how does the cooling capacity of an aircon compressor exceed that of the power supplied to it? from what i understand, energy cannot be created or destroyed. so when we put in 500W of electrical energy into a compressor, why do we expect the cooling capacity to be 1500W. does that mean that...