Recent content by weewooweee

using v^2 = u^2 + 2as, since in the horizontal direction acceleration is 0, v^2 = u^2 and they're the same value. Not sure though, haven't taken anything to do with forces so far, only 1D and 2D kinematics.

So I tried the following: Getting the velocities for x and y V_xi = 5.2cos(30) = 4.5 V_yi = 5.2sin(30) = 2.6 Then I use v^2 = u^2 +2as to get the final velocities before she leaves the ramp: for V_x the final is the same as the initial since the equation becomes V_xf = V_xi for V_y the final is...