Yes, I figured the physics at work was far more complicated than my texts led me to believe. I think I will just leave it be until I study more complicated mechanics.
Thanks.
I understand what you have written.
The precession of the wheel about the string means the system has an angular moment component parallel to the string. This means that a torque must have existed parallel to the string to start the precession in the first place. I am wondering where the...
I understand that diagram. The weight is pointing down, the radius is parallel to the axis of rotation, so torque is orthogonal, as the diagram shows. What I don't understand is where the force that causes the precession comes from. It is my understand that when something rotates about an...
I don't quite understand WHY a gyroscope precesses the way it does.
I'll set up an example in order to ask the questions I need.
Lets say you have a spinning bicycle wheel suspended at one end of its hub by a string. Due to the angular momentum of the spinning wheel, the wheel will precess...
This brings up a question about how a translating round object starts to rotate as it moves over a flat surface with no incline that has friction.
As the object moves initially, the point of the object in contact with the surface has a linear velocity equal to the velocity of the center of...
Right, so I'm wondering how the next part can ask for an initial and a final angular velocity about point O, when its well known that the angular momentum about O is always the same.
My problem is basically where they come up with this initial and final angular momentum when point O is...
This is driving me crazy. I need to make sure I'm reading my physics homework correctly.
Alright, a uniform, solid ball is pushed with initial velocity V(0) so that it slides. As the ball moves, kenetic friction between the ball and the surface it is traveling on causes the ball to rotate...
I made a mistake, the angle was nto given so I'm going to go with the traditional orientation of the axes to simplify things.
sumF(x) = W(man)-W(ladder)+N=0
sumF(y) =F(wall)-f=0
But I do not understand how I am missing a force. The only force the horizontal wall cna exert is the normal force because that horrizontal wall is frictionless, isn't that right? I appologize if I am missing something obvious.