Recent content by wilito92
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How Does Adding Different Dielectrics Affect a Capacitor's Performance?
Just though I'd leave some details here on how I solved it so anyone else having doubts with it can solve it too :) Part a: C=(Eo)*(A)/(d) = (8.85*10^-12)*(2.0*10^-4)/(2.0*10^-3)= 8.85*10^-13 F Part b: C1=(K1)*(Eo)*(A/2)/d=(3.5)*(8.85*10^-12)*((2.0*10^-4)/2)/(2.0*10^-3)=1.5487*10^-12...- wilito92
- Post #9
- Forum: Introductory Physics Homework Help
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How Does Adding Different Dielectrics Affect a Capacitor's Performance?
UPDATE: I was using the right formula.. just not using the correct Capacitance. U=(1/2)*(2.80*10^-12)*(12)^2=2.02*10^-10 Thanks for all the help!- wilito92
- Post #7
- Forum: Introductory Physics Homework Help
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How Does Adding Different Dielectrics Affect a Capacitor's Performance?
I was using U=(1/2)*C*(V)^2 but apparently the result I get is wrong... Is this the right formula?- wilito92
- Post #5
- Forum: Introductory Physics Homework Help
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How Does Adding Different Dielectrics Affect a Capacitor's Performance?
Hi, Thanks for the prompt response. I found the way to calculate the Capacitance after the dielectric. I calcualted C1 by using this formula: K1*E0*(A/2)/d then C2 and C3 using the same formula with there respectable K values and dividing the distance by two. However, now I am stuck on...- wilito92
- Post #3
- Forum: Introductory Physics Homework Help
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How Does Adding Different Dielectrics Affect a Capacitor's Performance?
Homework Statement A parallel plate capacitor of area 2 cm^2 is filled with three dielectrics with constants k1=3.5, k2=1.7 and k3=8.5. The dielectrics are placed as shown in the figure, each occupying half the total area, while the volume of the first double of the other two. If the...- wilito92
- Thread
- Capacitance Dielectrics
- Replies: 8
- Forum: Introductory Physics Homework Help