Recent content by williams31

A 56g steel ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact with it for .5 ms. The ball rebounds elastically, and returns to its original height. The time interval for a round trip is 8.00 s. In this situation, the average force...

i did not realize that...sorry..it is supposed to be .38m but i figured out the answer thanks to your help

i follow but i don't understand why r= 3.8 instead of .38

so it should be 1/2(3.7)(.38)^2 x 20?

i don't even see an equation in my book for a flat disk...i don't know what to do

for moment of inertia...i use the equation for a thin-walled hollow cylinder?

for some reason i am coming up with answers that are nowhere near close to the choices

do i use the equation L= r X mv?

just the whole problem...im not too smart when it comes to physics...every problem creates mess within my brain

now I am confused

im guessing no by the hint that was given after yours...is all the information given in the problem relevant...or is there some extra stuff in there

Angular momentum... A uniform disk has a mass of 3.7 kg and a radius of 3.8 m. The disk is mounted on frictionless bearings and is used as a turntable. The turntable is initially rotating at 20 rpm. A thing walled hollow cylinder has the same mass and radius as the disk. It is released from...

Im lost...but thanks for your guys help anyway.

Im not sure if I am following you.

A 56g steel ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact with it for .5ms. The ball rebounds elastically, and returns to its original height. The time interval for a round trip is 8.00s. In this situation, the average force...