Recent content by winblowzxp

I'm not exactly sure how to do that.

I worked out the node voltages and got 0V. For some reason I was thinking short circuit current. That would knock out that resistor, not a current source, sorry...been a long day/night/day. [PLAIN]http://www.fission-systems.com/images/physics/supernode.png

Ok. Sorry for changing things up so much. I just realized what the question was. After injection, the one next to your terminal pair will definitely be bypassed. I'd also say that the one coming off of the dependent source will also be bypassed and will give you a voltage divider. I'm not...

You usually inject 1A to get RTH. Since I don't see any independent sources, I'd say that the open circuit voltage is 0V.

I get: FB = -11.25 kN FT = -22.5 kN I figure that to get the force in the coupling (C), that I need to subtract FB from FT which would give me FC = -11.25 kN I know that fk = µN and that N in this case is -W. I'm not sure how to get the value for µ...

Change your current source into a voltage source, which should give you a 20V voltage source. When you redraw the circuit, put the resistor in series with the voltage supply and that will give you the voltage divider that gneill was referring to.

1.The 2-Mg truck is traveling at 15 m/s when the brakes on all its wheels are applied, causing it to skid for a distance of 10 m before coming to rest. Determine the constant horizontal force developed in the coupling C, and the frictional force developed between the tires of the truck and...