Recent content by wolfsprint

Re: Related time rate , ship problem Thanks for understanding , and i would like to know if my method of solving is correct please?

Re: Related time rate , ship problem ok so this is how i solved the problem : After t hours i presumed the following AB = 36+2t BC = 36+2t we need to find AC so AC^2 = (36+2t)^2 + (36+2t)^2 AC = 12(Root)[FONT=Arial]26 is this correct?

Re: Related time rate , ship problem so A is the origin and when the ship sails north i put a dot a bit further up and for the 30 north of east i draw an imaginary x-axis on the dot on the north direction and put a point in the 30 degrees direction? what's next?

Re: Related time rate , ship problem I understand i have to draw the x-axis and the y-axis and plot and join the dots to form a triangle but the problem is I am having trouble understanding the positions of the ships

[FONT=arial]A ship sailing west at 9am with velocity 20km/h. after one hour another ship sailed from the same port with velocity 40km/h at 60 north of west . find the rate of increase of the distance between the two ships at 11am Can someone please show me how to solve this? i have no idea

[FONT=arial]Ship started its journey from a Location A with velocity 18km/h to the north . after 2 hours the ship sailed in the direction 30 north of east find the rate of change in the distance between the location A and the position of the ship after 4 hours from the start. i have no idea how...

Thanks alot! i can't believe i missed that

i have no idea but I've read some where that a square based rectangular box is W^2h

Thanks a lot but i still didnt get what you are trying to tell me , I've got all these equations on the paper and i tried to substitute each in the original but it just won't get the right answer! the fact that dr/dt exists is not right :(:confused:

I still don't understand , what do you by "expressing"?

Vol. Of the cube is L^3 and vol of regtangular prism is Lxwxh , but i still can't find this relevant:(

The only equation i managed to find is v=4/3 "pi" r^3 which is he volume of the sphere. So if we say that the surface area = x ,then V=1/3 r . X But then when i differentiate it it turns out like this , Dv/dt = 1/3 dr/dt . Dx/dt , and that prove needs dv/dt = 1/2 r . Dx/dt

Can you please solve it and show me the work?

I tried and I couldn't, can you please show the work?

The volume of a sphere is = v cm^3, it's radius is = r cm, it's surface area is = x cm^2, prove that : dv/dt = 1/2 r.dx/dt