<i>An exceptional jumper could reach a vertical height of 0.75m. What force must a 75kg person exert to achieve this height? (assume the person crouches 0.30m to jump).</i>
Okay, I know that what I'm going to have to start with:
y = viy * t + 0.5 * g * t^2
to find max height at some...
Actually, it looks like what I am trying to solve is d = vi(t) + .5(a)t^2...
Accleration would seem to me to be 9.8m\s...
5m = vi(t) + .5(9.8)t^2
Grr, but how to solve for t?
d/t=v ?
Okay, so I was on the right-track on the second-one!
:
But... The first one still has me
In this problem I know it takes it d = at, or 20m = 340m\s * t
That would make .0588 = t, so it takes .0588 seconds for the speed to travel... 2.5s - .0588 = 2.441seconds left
.. Okay, so the ball...
Linear Motion (I'm sure it is easy for all you out there)
Okay, so I'm not really getting this problem:
"A bowling ball traveling at constant speed hits the pins at the end of the lane, 20m away. If the bowler hears the "crack" of the ball hitting the pins 2.5 s after releasing the ball. If...