Recent content by Worme

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    Resonant RLC circuit and in inductance

    Ok but what is the relation between frequencies and output/input?
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    Resonant RLC circuit and in inductance

    Yes C is not mentioneed and so is L. But i know that at resonance a RLC circuit has a frequency 1/(2*pi*sqrt(L*C)). So i know f and R.
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    Resonant RLC circuit and in inductance

    1. A resonant RLC circuit can be used as an amplifier for a certain band of frequencies around the resonant frequency. Consider a series RLC circuit as an audio band amplifier with an AC voltage source as the input, and the voltage across the 8.0Ω resistor as the output. The amplifier should...
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    What is the Inductance of Parallel Wires in a Circuit?

    1. Two wires running parallel to each other in a circuit can provide an inductance that is adjustable with their length. For the loop shown below with length L=2m , width w=5cm , and wire radius a=1mm , find the inductance in H?Homework Equations3. I thought i could find the inductance by...
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    Induced EMF in Coaxial Loops: Calculating Separation Distance

    Yes it was good , thanks a lot Hesch for your help.
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    Induced EMF in Coaxial Loops: Calculating Separation Distance

    If i use Faraday's law emf induced=-d(phi)/dt i could find B and by using Bior-Savart law on axis of a current loop , i would be abble to find thr separation between the loops?
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    Induced EMF in Coaxial Loops: Calculating Separation Distance

    Is the magnetic field produced by the large loop B=(muo*I)/(2*pi*r)?
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    Induced EMF in Coaxial Loops: Calculating Separation Distance

    1. A very large loop of metal wire with radius 1meter is driven with a linearly increasing current at a rate of 200amps/second . A very small metal wire loop with radius 5centimeter is positioned a small distance away with its center on the same axis (the loops are coaxial). The small loop...
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    Tangential acceleration of a proton in an increasing B

    How to find the tangential acceleration? By using Faraday's law E= - r/2 x dB/dt so a=E x q/m= -r/2 x dB/dt x q/m so a=- 5.22*10^4m/s^2
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    Tangential acceleration of a proton in an increasing B

    I use v=r*q*B/ r then put in m*a= qv x B and a= (B^2 x q^2 x r)/ m^2 but the acceleration seems so big!
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    Tangential acceleration of a proton in an increasing B

    1. Consider free protons following a circular path in a uniform magnetic field with a radius of 1meter . At t=0 , the magnitude of the uniform magnetic field begins to increase at 0.001Tesla/second . Enter the tangential acceleration of the protons in meters/second2 : positive if they speed...
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