%Assigement with restricted values (1)
x=normrnd(0,1,1,150e4); %generate standard normal numbers
y=1+(1-0.5).*rand(1,150e4); %generate uniform numbers in interval [0,1]
z=x./y; %desired new variable
hist(z);
%Tryings to verify that the experssion meet with (1)in
%means of histogram...