Recent content by Wyoming Physics

  1. W

    What is the amplitude of the electric field (laser reflection)

    Problem we are looking at :A laser beam has diameter 1.30 mm . The beam exerts a force of 3.7×10−9 N on a totally reflecting surface. What is the amplitude of the electric field of the electromagnetic radiation in this beam? (Emax) Relevant Formulas...etc.: I have the formula...
  2. W

    Possible title: How Deep Can a Tank be Filled Without the Window Failing?

    The only thing I can really think of is the integral from 1to3 (9800)(2)(d+4)dd
  3. W

    Possible title: How Deep Can a Tank be Filled Without the Window Failing?

    thank you I totally understand it now, although I am still confused about part b)
  4. W

    Possible title: How Deep Can a Tank be Filled Without the Window Failing?

    Wouldn't (4-h) measure the height I need? resulting in the answer being 58800N? sorry for so many questions, I am just very confused about this specific problem because we have not gone over this material in class
  5. W

    Possible title: How Deep Can a Tank be Filled Without the Window Failing?

    So when I set ip the integral from 1to3 of w*rho*g*h*dh, I get the integral from 1to3 of (2m)(1000kg/m^3)(9.8m/sec^2)(4-y), although when I solve for this I get 58800N.
  6. W

    Possible title: How Deep Can a Tank be Filled Without the Window Failing?

    I am assuming my error is with the height for which I put (4-y), since the window start 1m about the ground do I just subtract 4-1 and use 3m as my height?
  7. W

    Possible title: How Deep Can a Tank be Filled Without the Window Failing?

    Given: A Large tank has a plastic window on one wall that is designed to withstand a force of 90,000N. The square window is 2m on a side, and its lower edge is 1m from the bottom of the tank. Question: a) if the tank is filled to a depth of 4 m, will the window withstand the resulting force? b)...
  8. W

    Trouble with a basic fluid force problem

    Ahhh nevermind, I have been calculating the FORCE on the plate and not the PRESSURE on the plate which is P=F/A which would explain they I have to divide the force by 2.
  9. W

    Trouble with a basic fluid force problem

    What is the pressure on a horizontal surface with an area of 2m^2 that is 4m underwater? I tried to just use the formula: Force= (Density of water)(Area)(Depth)(gravity), plugging in the values Force=(1000kg/m^3)(2m^2)(4m)(9.8m/sec^2) and get 78400 N, when in reality the real answer is...
Back
Top