Recent content by WyzZero

Thank you very much for all your help.

ok, so maybe my math wasn't off, I did read you said you misunderstood that part of the problem so I'm hoping the following is correct. In regards to Planck's Law, when using L.H.: $$\lim_{\lambda \rightarrow \infty} \frac{40{\pi}kT\lambda^{-4}}{e^{\frac{hc}{kt\lambda}}} = \lim_{\lambda...

Thank you very much. This is making a lot more sense now. I will red the calculation and post my results tomorrow, perhaps if you have a second you could check it over real quick before I submit the assignment.

I see, I was on the right track by using l.h. Multiple times but I made an error in my math. So if I understand this correctly, I use L.H. once for ##\lambda \rightarrow \infty## and multiple times til ##\lambda^{x} = \lambda^{0}## for ##\lambda \rightarrow 0##

k, going from the fact that I over simplified, I will step back a few steps. So, with l'Hopital's Rule applied to: $$\frac{8{\pi}hc\lambda^{-5}}{e^{\frac{hc}{kT\lambda}}-1} = \frac{-40{\pi}hc\lambda^{-6}}{-\frac{hc}{kt\lambda^2}*e^{\frac{hc}{kt\lambda}}}$$ I use this to get...

Thanks, As I was walking out of the office, I was running through it in my head and thought the same thing, perhaps i simplified too far. I think i have the answer, will know once i get home to put it to paper.

Ok, next update. Looking into part b) and reading the other post and other info I've found. I see, to bring it about equal to R-J's Law, I need to find the Taylor polynomials of $$e^{\frac{hc}{kT\lambda}}$$ Using the Maclaurin series which gives $$e^{x} = \sum_ {n=0}^\infty \frac...

Noticed an error in my post, I fixed in the original post. I got it as it approached 0, not ##\infty##, to make sense.

First time here, and looking for help on this. The 2nd part of this problem, I have seen some posts on and am still reviewing, but haven't found much on the 1st part. Homework Statement 1) Use l'Hopital's Rule to show that $${\lim_{\lambda\rightarrow 0^{+}}=0}\text{ and...