Recent content by x2008kwa

Problem solved. Thank you very much for the help rl.bhat

I used that method, I = (.300kg)(.600)2/3 + (.300)(.600)2 and got the moment of inertia to be 0.144. I then used the formula T = I x α therefore (1.697) = (.144)α and got an answer of 11.8... which was incorrect. What am I doing wrong?

Homework Statement I'm getting this problem wrong and I'm not quite sure why. The 200 g model rocket shown in the figure generates 4.0 N of thrust. It spins in a horizontal circle at the end of a 100 g rigid rod. What is its angular acceleration (in rad/s2)? Homework Equations...

Thanks a ton for the help guys. Makes complete sense... Got the answer correct now. Much appreciated.

Thank you very much for your response. Yes, I do know that angular momentum should be conserved... and that L = I x w... Therefore I know that the angular momentum after the discs combine must be equal to the sum of all of the angular momentums of the individual discs... But I'm not...

Hi all, I've got a question that I'm stuck on. Three disks are spinning independently on the same axle without friction. Their respective rotational inertias and angular speeds are I,w (clockwise); 2I,3w (counterclockwise); and 4I,w/2 (clockwise). The disks then slide together and stick...