Yes, the two galaxies will combine into one larger galaxy but there will be very few actual collisions between the stars. Eventually, they will reach an equilibrium and thus becoming a new, much larger galaxy.
The NASA/IPAC EXTRAGALACTIC DATABASE (maintained by CalTech) is a great tool for stuff like this, and just in general an amazing catalog.
http://nedwww.ipac.caltech.edu/
Try their All-Sky Search (http://nedwww.ipac.caltech.edu/forms/byparams.html) and Limit it to Supernovae...when i did...
Never, the plane of the ecliptic is inclined about 63 degrees to the plane of the galaxy and the center of the galaxy is not at one of the nodes, therefore they will never be in a straight line.
Right, I was trying to give an overview of a rotating body. I didn't go specifically into the crab nebula because I was trying to be general, but I agree with you on the expansion causing the doppler shift in this instance.
Yes, there will be intermediate lines, sort of. There will be an extremely large amount intermediate lines, thus creating this sort of gradient, which will be extremely small and compacted, so for all practical purposes, it is just a tiny, unnoticeable part of the strong blue/red shift line.
This is kind of hard to explain, but if you consider a rotating body composed of many, many particles, the only place where there will be no red/blue shifting will be on a linear center of the nebula. However, in spectra, you can kind of think of it as an average. Yes, there is actually a...
Space Plasma Physics, as opposed to astrophysics which deals with the physics of all of space, usually addresses the physics of our local solar system. Space Plasma Physics usually deals the sun, its solar wind, planetary magnetospheres, aurora, and their interrelationship with one another...
I completely agree, however I was asked the difference between Kepler's and Newton's laws earlier and the difference is that Keplers is an approximation. For all practical purposes, as long as a much more massive object is present, much less massive objects's mass can be neglected. I am simply...
Again, it comes down to precision. I hold to my statement that two bodies of different masses will always revolve at different rates if at the same radii. When you say that you assume the primary mass is considerably larger, I agree, but it is not infinately larger. The only way for two...
Yes, that is what I am saying. If two objects have different masses and are their centers or mass are at the same radius from a massive body, they always will revolve at different speeds, always. Now in the case of the space shuttle and the ISS, there is a lot more to it than just this, you...
There are so many alternative theories to pioneer. I believe it is probably a miscalculation in acceleration, or the influence of the Kuiper Belt or dust or solar winds or something to that effect. The thing is, in such a relatively small distance, the pioneers have not sufficently gone...
I think the issue here is scale. The solar system is just too small and our current technology is not even close to being capable to detecting dark matter effects in such small amounts. Also, the dark matter proposes a halo which increases in mass as it extends outward. Because we are pretty...
If you use the second and the metre you need to have a conversion term, which is basically what Newton's formula comes up with. Try it out with the earth-sun system, seconds and metre's don't work in kepler's formula, you come up with nonsensical results.
Hopefully I can clear a couple things up:
p^2 = a^3 is only for bodies orbiting our sun where p must be in years and a must be in AU and it is only an approximation. A better formula is Newton's form of kepler's 3rd law:
p^2 = [(4*pi^2)/(G*(m+M))]*a^3
this formula can be easily defived...
Venus is at greatest elongation when the sun - venus - Earth system makes a 90 degree angle at venus's position. Knowing the distance from the Earth to the sun is 1AU, and using some trig, sin(47)*1AU ~ 0.73AU. The reason that this is .01 off of given, is because that given value is the mean...