Recent content by xannaxiero

  1. X

    U-tube filled with water and inmiscible liquid

    Do you think it could be because the tube is open to the atmosphere? Would that impact my formula at all?
  2. X

    U-tube filled with water and inmiscible liquid

    The answer ended up being .563 g/mL. Any idea why this is? There's no explanation with the homework :(
  3. X

    U-tube filled with water and inmiscible liquid

    Online homework...they're being graded as incorrect :'(
  4. X

    U-tube filled with water and inmiscible liquid

    Oops you're right, I'm sleepy >.< Its g/mL. My bad. That doesn't make any difference in the equation though does it? And yes, I'm assuming separation is in the bottom...this is supposed to be a pretty simple, standard u-tube problem, no tricks...
  5. X

    U-tube filled with water and inmiscible liquid

    Homework Statement A U-shaped tube is partly filled with water and partly filled with a liquid that does not mix with water. Both sides of the tube are open to the atmosphere. If h1 = 0.52 m and h2 = 0.16 m, what is the density of the liquid? Homework Equations ρ_{u}=h_{1}/h_{2} *...
  6. X

    Horizontal projectile, NOT GIVEN INITIAL VELOCITY

    velocity increases due to acceleration... a = change in velocity/change in time so we have a change from zero to 66.4 over the course of 9 seconds meaning acceleration is 7.4 m/s ? and i know v = vi + at so i feel like i could do v= 0 + 7.4*9 giving me 66.4, which is wrong.
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    Horizontal projectile, NOT GIVEN INITIAL VELOCITY

    ah yes. okay so that means 400 = uy*9 + 1/2 *9.8*9^2 so uy = .34 and i guess i did ux wrong, so ux is actually 600 = ux*9, giving ux = 67 but from here i still don't know how to find the final velocity
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    Horizontal projectile, NOT GIVEN INITIAL VELOCITY

    t = 9 sec so i did the following: 600 = uy + 1/2*9.8*9^2 solving for uy I got 22.6
  9. X

    Horizontal projectile, NOT GIVEN INITIAL VELOCITY

    u_{y} = 22.6 so if i do square root of 66.4^2 + 22.6^2 I should get my answer but i get 70.1 instead. how do you find the final based on the x and y components?
  10. X

    Horizontal projectile, NOT GIVEN INITIAL VELOCITY

    Homework Statement A cannon ball is fired horizontally off the top of a cliff that is 400 m high above the ocean. The ball hits the water 600 m away. With what speed does the cannon ball enter the water? Homework Equations I've tried using d_{x} = u_{x}*t d_{y} = u_{y}*t +...
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