Recent content by xiao

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    Specific Latent Heat of Fusion

    the experiment was easy just melt ice in water in room temp until u reach a certian temp but i find physics hard even the basics like this coz this is ment to be basic and i am not even a science student i am doing my BA in international relations and politics
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    Specific Latent Heat of Fusion

    lol by bad wooooohooo i did it
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    Specific Latent Heat of Fusion

    thanx mate even tho the answer is wrong atleast the math is write so i can put that in my Conclusion but thanks a lot for the help i still have to do the following experiment combustion of fules something on electricity something on water turbines something on solar energy biodiesel...
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    Specific Latent Heat of Fusion

    lol i know it means 382865.6041 Jouels per kilogram 382865.6041 Jouels is a HELL load of jouels to melt ice in water at room temprature 382865.6041 Jouels is like wat ur house used in 2 weeks (just guessing)
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    Specific Latent Heat of Fusion

    0.01258L + (0.01258)(4200)(-11) = 4235.2563 0.01258L + (-581.196) = 4235.2563 u mean subtract (-581.196) from 4235.2563 4235.2563 - (-581.196) 4816.4523 ?
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    Specific Latent Heat of Fusion

    ======================= my attempt at the final answer 0.01258kg x L (?) + 0.01258kg x 4200 Jkg-1K-1 x -11°K = 4235.2563 J 0.01258kg x L (?) = 4235.2563 J + 581.196 J L (?) = (4235.2563 J + 581.196 J) / 0.01258kg l (?) = 382865.6041 which i think is wrong coz i don't know wat i am doing
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    Specific Latent Heat of Fusion

    Heres a lil correction i made
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    Specific Latent Heat of Fusion

    Homework Statement need to work out the Specific Latent Heat of Fusion i did the experiment and here are the results Results: Mass of calorimeter Mcal 116.87g Mass of H2O MH2O = [Mcal + H2O] - Mcal 80.82g (197.69g) Mass of Ice Mice = [Mcal + Mice + H2O] - MH2O 12.58g (210.27g) Room...
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