Recent content by XPX1

That dosn't make any sense to me! v0 = 0... Ok v = 0+at now how do I figure out acceleration and time!? Can somebody please do an equation of this so I can see how this works out, I've been trying to figure out this problem for 3 days now, and I've had no luck.

But.. How can I solve for acceleration if I can't solve for time!? Please help!

I have vi=90 mi/hr mass=0.15 xf=1.6 I can't do anything with this information! I've tried velocity versus time graphs, position versus time graphs, everything! It seems like this problem does not give me enough information to solve it!

any ideas?

Any help on how to plug this in? Now that I have the velocity, I need to find the time, dang these problems are confusing, how do I figure out the time!?

I don't know what vi=? is vi=90? or is that vf?

Also, what does it mean by (a) what is the magnitude of the average force exerted on the ball during the pitch!?

Homework Statement In baseball, a pitcher can accelerate a 0.15 kg ball from rest to 90 mi/h in a distance of 1.6 m. (a) What is the magnitude of the average force exerted on the ball during the pitch? ____N Homework Equations a=d/t xf=xi+vixt+1/2(a)t^2 Fnet=ma The Attempt...

-5.763 kN was not correct, I still don't understand!

so how do I convert -5763 to kiloNewtons? Infact what is -5763? If the mass is kilograms and the acceleration was in.. meters? Then.. -5763 would be kilograms right? 1 kilogram = 9.8 Newtons? and 1000 Newtons = 1 kiloNewton? so -5763 would be -57630?

Woohoo I got b. correct! But now for a. Fnet=MA then Fnet= 1020(-5.65) Fnet = -5763 Then the average force exerted on the car while breaking is -5763 kN? kN I am guessing is kiloNewtons?

I plugged it into the position versus time graph and got xf=14.663 xf=xi+vixt+.5at^2 xf=0+16(1.15)+.5(-5.65)(1.15)^2

but how do I find xf or xi if I know xi = 0 and xf = ?

well b should be -5.65(1.15) which = -6.4975 but that is not correct for b. and if I was to do the Fnet I would assume that Fnet=MA Fnet= 1020(-5.65) right?

im still kind of confused, I think the equations I need to use for acceleration are vf=vi+axt, but I still got the question wrong, even for part b where it asks me how far it went! Somebody please halp! vf=vi+axt then 9.5=16+1.15a -6.5=1.15a a=-5.65 am I not correct?