Recent content by xxglamisxx

youre right, that was a mistake on my part. to answer your question the normal force would be 0 degrees. for my x gravity component for m1 i changed it to cos 60 and respectively for the y component. However, thanks to some guidance from @gneill i solved the problem. method: derived my...

Ok so I re wrote the problem, with FBDs for each mass, and used θ instead of phi here is a picture of what i have:

going to start over on this problem fresh, but I am currious...is there a way to find theta before

let me see what i can do about the picture, as for the X and Y axis, each mass has its own. The one on the left, M1, has its Y axis along the left leg of the triangle, and M2 has its Y axis along the right leg of the triangle, the X's are perpendicular to their respective Y axis phi was...

Sure. Note: angle phi referenced below is the angle between horizontal and our tension cable on the right. for M1 i have: sum of forces in the x: N(sub1) = -G(sub1)cos(30) + T(sub1)sin(phi) sum of forces in the y: T(sub1) = (G(sub1)cos(30)) / (sin(phi)M2 sum of forces in the x...

well I start with a FBD for each mass and and rotate the Cartesian coordinates so that the y-axis is along the sides of the triangle for each mass and the x-axis follows the normal force. I sum the x and y components to zero solving for either the normal force or tension force. I begin to have...

Homework Statement A rigid wire frame is formed in a right triangle, and set in a vertical plane as shown. Two beads, of weight W1 = 1.5 N and W2 = 2.5 N, slide without friction on the wires, and are connected by a cord. When the system is in static equilibrium, what is the tension in the...